12-(3x^2+5x)+(-8x+3x^2)=0

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Solution for 12-(3x^2+5x)+(-8x+3x^2)=0 equation:


Simplifying
12 + -1(3x2 + 5x) + (-8x + 3x2) = 0

Reorder the terms:
12 + -1(5x + 3x2) + (-8x + 3x2) = 0
12 + (5x * -1 + 3x2 * -1) + (-8x + 3x2) = 0
12 + (-5x + -3x2) + (-8x + 3x2) = 0

Remove parenthesis around (-8x + 3x2)
12 + -5x + -3x2 + -8x + 3x2 = 0

Reorder the terms:
12 + -5x + -8x + -3x2 + 3x2 = 0

Combine like terms: -5x + -8x = -13x
12 + -13x + -3x2 + 3x2 = 0

Combine like terms: -3x2 + 3x2 = 0
12 + -13x + 0 = 0
12 + -13x = 0

Solving
12 + -13x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -13x = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -13x = 0 + -12
-13x = 0 + -12

Combine like terms: 0 + -12 = -12
-13x = -12

Divide each side by '-13'.
x = 0.9230769231

Simplifying
x = 0.9230769231

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